combine the terms and write the answer as one logorithm. Please show work.
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Answer:[tex]ln(x^{\frac{1}{4}}y^{\frac{1}{2}}z^{\frac{2}{3}})[/tex]
Step-by-step explanation:
Formula:
[tex]k\times ln(a)=ln(a^{k})[/tex]
[tex]ln(a)+ln(b)=ln(ab)[/tex]
[tex]ln(a)-ln(b)=ln(\frac{a}{b})[/tex]
[tex]\frac{1}{4}\times ln(x)=ln(x^{\frac{1}{4}})[/tex]
[tex]\frac{-1}{2}\times ln(x)=ln(x^{\frac{-1}{2}})[/tex]
[tex]\frac{2}{3}\times ln(x)=ln(x^{\frac{2}{3}})[/tex]
Working:
So,[tex]\frac{1}{4}ln(x)-\frac{1}{2}ln(y)+\frac{2}{3}ln(z)=ln(x^\frac{1}{4})-ln(y^\frac{-1}{2})+ln(z^\frac{2}{3})[/tex]
=[tex]ln(\frac{x^\frac{1}{4}}{y^{\frac{-1}{2}} } )+ln(z^{\frac{2}{3}})[/tex]
=[tex]ln(x^\frac{1}{4}}{y^{\frac{1}{2}}z^{\frac{2}{3} })[/tex]