Answer:
2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → 1Al₂(SO₄)₃(s) + 6NaNO₃(aq)
2, 3, 1, 6
Second choice.
Step-by-step explanation:
Count the number of atoms on each side. Keep polyatomic ions together because they exist on both sides. After each coefficient you write in, recount the number of atoms.
Al(NO₃)₃(aq) + Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)
Al 1 Al 2
NO₃ 3 NO₃ 1
Na 2 Na 1
SO₄ 1 SO₄ 3
Balance the sulfates (SO₄) by multiplying it by 3 on the left. Sodium (Na) will also change.
Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)
Al 1 Al 2
NO₃ 3 NO₃ 1
Na 6 Na 1
SO₄ 3 SO₄ 3
Balance sodium (Na) by multiplying it on the left by 6. Nitrate (NO₃) will also change.
Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)
Al 1 Al 2
NO₃ 3 NO₃ 6
Na 6 Na 6
SO₄ 3 SO₄ 3
Balance the number of nitrates (NO₃) on the left. Multiply by 2. Aluminum (Al) also changes.
2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)
Al 2 Al 2
NO₃ 6 NO₃ 6
Na 6 Na 6
SO₄ 3 SO₄ 3
The same number of each atom is on each side, so the equation is balanced.
If there is no coefficient, treat it as 1.
2,3,1,6
