Answer:
Standard form of polynomial with zeros 2 and -8 is[tex]P(x) = x^2 + 6x - 16[/tex]
Step-by-step explanation:
Here, the zeroes of the polynomial P(x) is given as x = 2 and x = -3
If x = a is a zero pf the polynomial p(x) , then (x-a) is the root of the given polynomial.
⇒ (x- 2) and (x -(-8)) are the two roots of the polynomial P(x).
Now, Polynomial P(x) = Product of all its Roots
[tex]⇒P(x) = (x- 2) (x +8 )\\= x(x+8) -2(x+8) = x^2 + 8x - 2x- 16\\= x^2 + 6x - 16 \\\implies P(x) = x^2 + 6x - 16[/tex]
Hence the standard form of polynomial with zeros 2 and -8 is[tex]P(x) = x^2 + 6x - 16[/tex]