Find the measure of Angle B
A. 50°
B. 55°
C. 60°
D. 65°

Option B. 55° is the correct answer
Step-by-step explanation:
"The sum of interior angles of a triangle is always 180°"
Given
m∠A=(3x+1)°
m∠B=(2x-1)°
m∠C = 40°
We know that
m∠A+m∠B+m∠C=180°
Putting the values of angles
[tex](3x+1) +(2x-1) +40 = 180\\3x+1+2x-1+40 = 180\\5x+40=180\\[/tex]
Subtracting 40 from both sides
[tex]5x+40-40=180-40\\5x=140[/tex]
Dividing both sides by 5
[tex]\frac{5x}{5} = \frac{140}{5}\\x=28[/tex]
We have to find Angle B,
So
m∠B = 2x-1 = 2(28)-1 = 56-1 = 55°
Hence,
m∠B=55°
Option B. 55° is the correct answer
Keywords: Triangle, Interior angles
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