Question

Solve the following system of equations by substitution and show work.
​y=−3x−12
−6x+4y=−12

Answer 1

The solution of the given system of linear equations is:

x=-2, y=-6

Step-by-step explanation:

Given

$y=-3x-12\ \ \ \  Eqn\ 1\\-6x+4y=-12\ \ \ \  Eqn\ 2\\Put\ y=-3x-12\ in\ Eqn\ 2\\-6x+4(-3x-12)=-12\\-6x-12x-48=-12\\-18x=-12+48\\-18x=36\\Dividing\ both\ sides\ by\ -18\\\frac{-18x}{-18}=\frac{36}{-18}\\x=-2\\Putting\ x=-2\ in\ Eqn\ 1\\y=-3(-2)-12\\y=6-12\\y=-6$

Hence,

The solution of the given system of linear equations is:

x=-2, y=-6

Keywords: Linear Equations, Variables

Learn more about linear equations at:

• brainly.com/question/2115122
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