Question

The air in a bicycle tire is bubbled through water and collected at 25 ∘C. If the total volume of gas collected is 5.30 L at a temperature of 25 ∘C and a pressure of 737 torr , how many moles of gas was in the bicycle tire?

Answer 1

Answer: The number of moles of gas in bicycle tire is 0.210 moles

Explanation:

To calculate the moles of gas, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 737 torr

V = Volume of the gas = 5.30 L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of gas = ?

Putting values in above equation, we get:

$737Torr\times 5.30L=n\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 298K\\\\n=\frac{737\times 5.30}{62.364\times 298}=0.210mol$

Hence, the number of moles of gas in bicycle tire is 0.210 moles

Answer 2

There were 0.2 moles of gas originally in the tire.

Pressure of gas = Total pressure - vapor pressure of water

Pressure of gas (P) =  737 torr - 23.8 torr= 713.2 torr or 0.94 atm

Volume (V)= 5.30 L

Temperature (T) = 25 ∘C or 298 K

number of moles (n) = ?

Gas constant (R) = 0.082 atm LK-1mol-1

From PV = nRT

n = PV/RT

n = 0.94 atm × 5.30 L/0.082 atm LK-1mol-1  × 298 K

n = 0.2 moles

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