Respuesta :
Answer:
[tex]y=128(\frac{1}{2} )^{x-1}[/tex]
Step-by-step explanation:
This problem models a geomatric sequence, because each new element is half of the last one.
A geometric sequence is defined as
[tex]a_{n}=a_{1}r^{n-1}[/tex]
Where [tex]n[/tex] is the position of the element, [tex]a_{1}[/tex] is the first element and [tex]r[/tex] is the reason that creates the sequence.
In this case, we have
[tex]a_{1}=128[/tex], [tex]r=\frac{1}{2}[/tex]
Replacing this values, we have
[tex]a_{n} =128(\frac{1}{2})^{n-1}[/tex]
Where [tex]n[/tex] is the independent variable and [tex]a_{n}[/tex] is the dependent variable.
Therefore, the function that relates the number of rounds and the number of players advaincing to the next round is
[tex]y=128(\frac{1}{2} )^{x-1}[/tex]