What is the slope of line segment AB?
A) 2/3
B) 3/4
C) 4/3
D) -3/4

For this case we have that by definition, the slope of a line is given by:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
Where:
[tex](x_ {1}, y_ {1})[/tex]and [tex](x_ {2}, y_ {2})[/tex]are two points through which the line passes.
According to the image we have:
[tex](x_ {1}, y_ {1}): (-5,3)\\(x_ {2}, y_ {2}): (3, -3)[/tex]
Substituting we have:
[tex]m = \frac {-3-3} {3 - (- 5)} = \frac {-6} {3 + 5} = \frac {-6} {8} = - \frac {3} {4}[/tex]
Thus, the slope of the line is:
[tex]m = - \frac {3} {4}[/tex]
Answer:
[tex]m = - \frac {3} {4}[/tex]
Answer:
D) [tex]\displaystyle -\frac{3}{4}[/tex]
Step-by-step explanation:
B[3, −3] and A[−5, 3]
[tex]\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-3 - 3}{5 + 3} = -\frac{6}{8} = -\frac{3}{4}[/tex]
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