Respuesta :

Answer:

• exterior angle of a triangle is equal to sum of opposite interior angle

(6x-7) = (103-x) + 2x

6x-7 = 103 - x + 2x

6x-7 = 103 + x

6x - 7 - x -103 = 0

6x - x - 110 = 0

5x - 110 = 0

5x = 110

x = 110/5

x = 22

as exterior angle is (6x-7)

= 6 × 22 - 7

= 125

-> Exterior angle is 125°

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