Question

Suppose a distant world with surface gravity of 5.20 m/s2 has an atmospheric pressure of 7.16 ✕ 104 Pa at the surface. (a) What force is exerted by the atmosphere on a disk-shaped region 2.00 m in radius at the surface of a methane ocean

Answer 1

Answer:

899752.13598 N

Explanation:

p = Pressure on the plate = $7.16\times 10^4\ Pa$

A = Area = $\pi r^2=\pi 2^2=\pi 4$

F = Force on the region

When force is divided by area we get pressure

$p=\frac{F}{A}\\\Rightarrow F=p\times A\\\Rightarrow F=7.16\times 10^4\times \pi 4\\\Rightarrow F=899752.13598\ N$

Force is exerted by the atmosphere on a disk-shaped region is 899752.13598 N