The average NASCAR race car weighs 3400 lb. At a recent Nascar race the cars went flying around the banked curves at a raceway. The banking of the turns at the raceway are θ = 29°. Hint 1: you will want to convert the units given to kg and m/s first. Hint 2: The horizontal component of the normal force supplies the needed centripetal force in this case (not the friction force). (a) What is the algebraic expression for the component of the normal force in the vertical direction? (Use the following as necessary: FN and θ.)

Respuesta :

Idk to be honest you would have to mutiply

The expression used to find normal force is required.

The expression is [tex]F_N=\dfrac{mg}{\cos\theta}[/tex].

m = Mass of car = 3400 lb

[tex]\theta[/tex] = Angle = [tex]29^{\circ}[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Converting lb to kg

[tex]1\ \text{lb}=0.4536\ \text{kg}[/tex]

[tex]3400\ \text{lb}=3400\times 0.4536=1542.24\ \text{kg}[/tex]

Normal force is given by

[tex]F_N=\dfrac{mg}{\cos\theta}\\ =\dfrac{1542.24\times 9.81}{\cos29}\\ =17298.23\ \text{N}[/tex]

The normal force in the vertical direction is 17298.23 N.

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