Question

A parallel-plate capacitor with circular plates is being charged. Consider a circular loop centered on the central axis and located between the plates. If the loop radius of 4.95 cm is greater than the plate radius, what is the displacement current between the plates when the magnetic field along the loop has magnitude 3.69 µT?

Answer 1

Answer:

$I=0.9132A$

Explanation:

The magnetic field in a circular plates

$\beta=\frac{u_o*I}{2\pi*r}$

$u_0=4\pi x10^{-7}T*m/A$

Solve to current

$I=\frac{2\pi*r*\beta}{u_0}$

replacing

$I=\frac{2\pi*49.5x10^{-3}m*3.69x10^{-6}T}{4\pi x10^{-7}T*m/A}$

$I=0.9132A$