Respuesta :
Answer:
HBr, HF, HC₂H₃O₂, HC₆H₅O
Explanation:
Rank the solutions in order of decreasing [H₃O⁺]. Rank solutions from largest to smallest hydronium ion concentration. To rank items as equivalent, overlap them.
- HC₂H₃O₂ 0.10 M (acetic acid)
- HF 0.10 M
- HBr 0.10 M
- HC₆H₅O 0.10 M (phenol)
For weak acids, the concentration of H₃O⁺ can be calculated using the following expression:
[H₃O⁺] = √(Ka × Ca)
where,
Ka is the acid dissociation constant
Ca is the initial concetration of the acid
For monoprotic strong acids, the concentration of H₃O⁺ is:
[H₃O⁺] = Ca
HC₂H₃O₂ 0.10 M (acetic acid)
Acetic acid is a weak acid that ionizes according to the following equaion:
HC₂H₃O₂(aq) + H₂O(l) ⇄ C₂H₃O₂(aq)⁻ + H₃O⁺(aq)
[H₃O⁺] = √(Ka × Ca) = √(1.8 × 10⁻⁵ × 0.10) = 1.3 × 10⁻³ M
HF 0.10 M
HF is a weak acid that ionizes according to the following equation:
HF(aq) + H₂O(l) ⇄ F⁻(aq) + H₃O⁺(aq)
[H₃O⁺] = √(Ka × Ca) = √(6.6 × 10⁻⁴ × 0.10) = 8.1 × 10⁻³ M
HBr 0.10 M
HBr is a strong acid that ionizes according to the following equation:
HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)
[H₃O⁺] = Ca = 0.10 M
HC₆H₅O 0.10 M (phenol)
Phenol is a weak acid that ionizes according to the following equation:
HC₆H₅O(aq) + H₂O(l) ⇄ C₆H₅O(aq)⁻(aq) + H₃O⁺(aq)
[H₃O⁺] = √(Ka × Ca) = √(1.3 × 10⁻¹⁰ × 0.10) = 3.6 × 10⁻⁶ M