Question

An airline pilot pulls her 12.0 kg rollaboard suitcase along the ground with a force of 25.0 N for 10.0 meters. The handle she pulls on makes an angle of 36.5 degrees with the horizontal. How much work does she do over the ten-meter distance?

Answer 1

Answer:

Work she does = 200.96 J

Explanation:

Work done is the dot product of force and displacement.

         $W=\vec{F}.\vec{S}=FScos\theta$

An airline pilot pulls her 12.0 kg roll aboard suitcase along the ground with a force of 25.0 N for 10.0 meters. The handle she pulls on makes an angle of 36.5 degrees with the horizontal.

So we have

            Force, F = 25 N

            Displacement, S = 10 m

            Angle, θ = 36.5°

    Work done, W = FScosθ = 25 x 10 x cos 36.5 = 200.96 J

Work she does = 200.96 J