Answer:[tex]\frac{1}{96}[/tex]
Step-by-step explanation:
Given three bags with Probabilities of heads bring is 0.5,0.6 and 0.4
A coin is randomly Picked and tossed until heads Appears
Probability of choosing a fair coin is [tex]P_1=\frac{1}{3}[/tex]
because coin with Probability of getting head 0.5 is fair one
Probability of getting head at 5 th toss is
[tex]P_2=\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{2^5}[/tex]
Thus Probability that the coin is fair, if the first head appears on 5 th toss
is given by
[tex]P=P_1\times P_2[/tex]
[tex]P=\frac{1}{3}\times \frac{1}{2^5}=\frac{1}{96}[/tex]