USE K U E S
Problem 1.
A runner accelerates to 4.2 m/s2 for 100 seconds before winning the race. How far did he/she run?

Problem 2.
A plane starts from rest and accelerates uniformly over a time of 25 s for a distance of 300 m. Determine the plane’s acceleration.

Problem 3.
A ball free falls from the top of the roof for 5 seconds. How far did it fall? What is its final velocity at the end of 5 seconds?​

Respuesta :

Explanation:

Problem 1.

Initial speed of the runner, u = 0

Acceleration of the runner, [tex]a=4.2\ m/s^2[/tex]

Time taken, t = 100 s

Let v is the speed of the runner now. Using the first equation of kinematics as :

[tex]v=u+at[/tex]

[tex]v=at[/tex]

[tex]v=4.2\ m/s^2\times 100\ s[/tex]

v = 420 m/s

Problem 2.

Initial speed of the plane, u = 0

Distance covered, d = 300 m

Time taken, t = 25 s

Using the equation of kinematics as :

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

[tex]d=\dfrac{1}{2}at^2[/tex]

[tex]a=\dfrac{2d}{t^2}[/tex]

[tex]a=\dfrac{2\times 300\ m}{(25\ s)^2}[/tex]

[tex]a=0.96\ m/s^2[/tex]

Problem 3.

A ball free falls from the top of the roof for 5 seconds. Let it will fall at a distance of d. It is given by :

[tex]d=ut+\dfrac{1}{2}gt^2[/tex]

[tex]d=\dfrac{1}{2}\times 9.8\times (5)^2[/tex]

d = 122.5 meters

Let v is the final speed at the end of 5 seconds. Again using first equation of kinematics as :

[tex]v=u+gt[/tex]

[tex]v=9.8\ m/s^2\times 5\ s[/tex]

v = 49 m/s

Hence, this is the required solution.

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