Explanation:
Problem 1.
Initial speed of the runner, u = 0
Acceleration of the runner, [tex]a=4.2\ m/s^2[/tex]
Time taken, t = 100 s
Let v is the speed of the runner now. Using the first equation of kinematics as :
[tex]v=u+at[/tex]
[tex]v=at[/tex]
[tex]v=4.2\ m/s^2\times 100\ s[/tex]
v = 420 m/s
Problem 2.
Initial speed of the plane, u = 0
Distance covered, d = 300 m
Time taken, t = 25 s
Using the equation of kinematics as :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
[tex]d=\dfrac{1}{2}at^2[/tex]
[tex]a=\dfrac{2d}{t^2}[/tex]
[tex]a=\dfrac{2\times 300\ m}{(25\ s)^2}[/tex]
[tex]a=0.96\ m/s^2[/tex]
Problem 3.
A ball free falls from the top of the roof for 5 seconds. Let it will fall at a distance of d. It is given by :
[tex]d=ut+\dfrac{1}{2}gt^2[/tex]
[tex]d=\dfrac{1}{2}\times 9.8\times (5)^2[/tex]
d = 122.5 meters
Let v is the final speed at the end of 5 seconds. Again using first equation of kinematics as :
[tex]v=u+gt[/tex]
[tex]v=9.8\ m/s^2\times 5\ s[/tex]
v = 49 m/s
Hence, this is the required solution.