Question

17. If 3.25 g of Na2CO3 is used, how many grams of CaCO3 can be
made?​

Answer 1

Answer:

Mass of CaCO₃  = 3 g

Explanation:

Given data:

Mass of sodium carbonate = 3.25 g

Mass of calcium carbonate produced = ?

Solution:

Chemical equation:

CaCl₂ + Na₂CO₃  →  CaCO₃ + 2NaCl

Moles of Na₂CO₃:

Number of moles = mass/ molar mass

Number of moles =  3.25 g / 106 g/mol

Number of moles = 0.03 mol

Now we will compare the moles of sodium carbonate with calcium carbonate.

                              Na₂CO₃    :       CaCO₃

                                    1           :       1

                                  0.03        :      0.03

Mass of calcium carbonate:

Mass = number of moles × molar mass

Mass =   0.03  mol  ×  100 g/mol

Mass = 3 g