Use the coordinates of the labeled point to find the point-slope equation of the line.
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For this case we have that by definition, the equation of a line of the point-slope form is given by:
[tex]y-y_ {0} = m (x-x_ {0})[/tex]
Where:
m: It's the slope
[tex](x_ {0}, y_ {0})[/tex]: It is a point through which the line passes
To find the slope, we need two points through which the line passes, observing the image we have:
[tex](x_ {1}, y_ {1}): (3, -5)\\(x_ {2}, y_ {2}): (0,4)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {4 - (- 5)} {0-3} = \frac {4 + 5} {-3} = \frac {9} {- 3} = - 3[/tex]
Thus, the equation is of the form:
[tex]y-y_ {0} = - 3 (x-x_ {0})[/tex]
We choose a point:
[tex](x_{0}, y_ {0}) :( 3, -5)[/tex]
Finally, the equation is:
[tex]y - (- 5) = - 3 (x-3)\\y + 5 = -3 (x-3)[/tex]
Answer:
[tex]y + 5 = -3 (x-3)[/tex]
Option D