Start with
[tex]3\sqrt{10}+7\sqrt{15}-6\sqrt{10}-4\sqrt{15}[/tex]
We can factor the square root of 10 between the 1st and 3rd term, and the square root of 15 between the remaining two:
[tex]\sqrt{10}(3-6)+\sqrt{15}(7-4) = -3\sqrt{10}+3\sqrt{15}[/tex]
Now we can factor 3 from both terms:
[tex]3(\sqrt{15}-\sqrt{10})[/tex]
You can also use the rule
[tex]\sqrt{ab}=\sqrt{a}\sqrt{b}[/tex]
To observe that
[tex]3(\sqrt{15}-\sqrt{10})=3(\sqrt{5}\sqrt{3}-\sqrt{5}\sqrt{2})[/tex]
So we can factor the square root of 5 as well:
[tex]3\sqrt{5}(\sqrt{3}-\sqrt{2})[/tex]
And the expression is fully simplified.