Question

Blood can carry excess energy from the interior to the surface of the body, where the energy is dispersed in a number of ways. While a person is exercising, 0.6 kg of blood flows to the body’s surface and releases 2000 J of energy. The blood arriving at the surface has the temperature of the body’s interior, 37.0 °C. Assuming that blood has the same specific heat capacity as water, determine the temperature of the blood that leaves the surface and returns to the interior.

Answer 1

Answer:

$T = 36.2 ^oC$

Explanation:

As we know that heat released is given as

$Q = ms \Delta T$

here we know that

Q = 2000 J

m = 0.6 kg

s = 4186 J/kg C

now from above equation we have

$2000 = 0.6(4186)(37 - T)$

$2000 = 2511.6 (37 - T)$

$T = 36.2 ^oC$

Answer 2

The temperature of the blood that leaves the surface and returns to the interior assuming it has the same specific heat capacity as water is 36.2 °C

Data obtained from the question

• Mass of blood (M) = 0.6 Kg = 0.6 × 1000 = 600 g
• Initial temperature (T₁) = 37 °C  
• Specific heat capacity (C) = 4.184 J/gºC
• Heat (Q) = –2000 J (released energy)

• Final temperature (T₂) =?

How to determine the temperature

Q = MC(T₂ – T₁)

–2000 = 600 × 4.184 (T₂ – 37)

–2000 = 2510.4 (T₂ – 37)

Divide both side by 2510.4

–2000 / 2510.4 = T₂ – 37

–0.8 = T₂ – 37

Collect like terms

T₂ = – 0.8 + 37

T₂ = 36.2 °C

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