Question

Can someone please help me!

Answer 1

Answer:

Problem 5:

Answer a) = 16 m

JH = 14 m

GJ = 19 m

answer d) = $105^o$

< G  = $34^o$

< J =  $41^o$

Problem 6:

x = 13

Step-by-step explanation:

Problem 5: Notice from the drawing that the following vertices are congruent:

G same as D

J same as E

and

H same as the remaining vertex

Therefore DF = GH = 16 m

JH = EF = 14 m

GJ = DE = 19 m

and for the angles:

< H = $105^o$ and equal to its equivalent in the other triangle.

< G = < D = $34^o$

and the remaining angle (<J) can be obtained by using that the addition of the three angles in a triangle should equal $180^o$. That is: <J + <H + <G = $180^o$, therefore <J + $34^o$ + $105^o$ =  $180^o$, then:

<J =  $180^o$ - $34^o$ - $105^o$ = $41^o$

Problem 6: An equilateral triangle has all equal sides, and therefore all equal angles opposing the sides. Therefore all three angles must be equal, and add to $180^o$, Then each angle should be equal to $180^o$/3 = $60^o$.

So in order to find "x" we need to find the unknown that makes the following equation true:

8 x - 44 = 60

8 x = 60 + 44

8 x = 104

x = 104/8

x = 13