Question

TEEL
4. A fish was caught. Its tail weighed 9 lbs. Its head weighed as much as its tail plus half its
body. Its body weighed as much as its head and tail. What did the fish weigh?​

Answer 1

Answer:

72 lbs

Explanation:

Tail weight is TW.

Head weight is HW.

Body weight is BW

TW=9 lbs.

HW=TW+(BW/2)

BW=TW+HW

$TW=9\\HW=TW+(BW/2)\\BW=TW+HW\\BW=HW+9$

Since HW=BW/2+9 inserting it in BW=HW+9

$BW=9+(BW/2)+9\\BW=18+(BW/2)\\BW-BW/2=18\\\\BW/2=18\\BW=36\\Total weight=BW+HW+TW$

Inserting BW value in HW=9+BW/2

$HW=9+(36/2)\\HW=27\\TW=9\\Total Weight=36+27+9\\Total Weight=72 lbs$