Question

A 2.6 kg object is accelerated from rest to a
speed of 22 m/s in 22 s.
What average force was exerted on the ob-
ject during this period of acceleration?

Answer 1

Answer:

2.6 N

Explanation:

Given:

v₀ = 0 m/s

v = 22 m/s

t = 22 s

Find: a

v = at + v₀

(22 m/s) = a (22 s) + (0 m/s)

a = 1 m/s²

Newton's second law:

F = ma

F = (2.6 kg) (1 m/s²)

F = 2.6 N