Answer:
60.272 g
Explanation:
We are given;
- Molecules of C₂H₄O₂ are 6.00 × 10^23 molecules
We are required to calculate mass of C₂H₄O₂
- We know that one mole of a compound contains a number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules
- That is, 1 mole of a compound = 6.022 × 10^23 molecules
In this case;
1 mole of C₂H₄O₂ = 6.022 × 10^23 molecules
But, Molar mass of C₂H₄O₂ = 60.052 g/mol
Therefore;
60.052 g = 6.022 × 10^23 molecules
Mass of C₂H₄O₂ = (60.052 g × 6.022 × 10^23) ÷ 6.00× 10^23
= 60.272 g
Therefore, the mass of C₂H₄O₂ in 6.00 × 10^23 molecules is 60.272 g
