Answer:
The data shows a proportion in car commuting greater than 8%
Step-by-step explanation:
Five years ago, a survey found that the proportion of city employees who commute to work by car is 8%.
Claim : . A local city commissioner claims that the percentage is higher than it was five years ago.
[tex]H_0:p=0.08\\H_a:p>0.08[/tex]
A random sample of 1000 employees was collected
n = 1000
They found 12% of employees commute by car.
No. of employees commute by car = [tex]\frac{12}{100} \times 1000=120[/tex]
We will use one sample proportion test
x= 120
n = 1000
[tex]\widehat{p}=\frac{x}{n}[/tex]
[tex]\widehat{p}=\frac{120}{1000}[/tex]
[tex]\widehat{p}=0.12[/tex]
Formula of test statistic =[tex]\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
=[tex]\frac{0.12-0.08}{\sqrt{\frac{0.08(1-0.08)}{1000}}}[/tex]
=[tex]4.66[/tex]
Significance level = 10%
α=0.1
[tex]Z_{0.10}=1.28[/tex](Using z table)
So, test statistic i.e.Z calculated > Z critical
So, we failed to accept null hypothesis .The data shows a proportion in car commuting greater than 8%