The acceleration of the ball in the vertical direction is [tex]9.8 m/s^2[/tex], downward.
Explanation:
This is a typical example of projectile motion, which consists of two independent motions:
- A uniform horizontal motion at constant velocity (since there are no forces in the horizontal direction)
- A vertical accelerated motion at constant acceleration (due to the presence of the force of gravity)
We are considering now the vertical motion only. There is only one force acting on the ball in this direction: the force of gravity, of magnitude
F = mg
where m is the mass of the ball and [tex]g=9.8 m/s^2[/tex] the acceleration due to gravity, downward. This means that the acceleration of the ball in this direction is (using Newton's second law)
[tex]a=\frac{F}{m}=\frac{mg}{m}=g = 9.8 m/s^2[/tex]
Therefore, the acceleration of the ball in the vertical direction is [tex]9.8 m/s^2[/tex], downward.
Learn more about projectile motion:
brainly.com/question/8751410
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