Answer:
Small pitcher holds 2 cups of water
Large pitcher holds 4 cups of water
Step-by-step explanation:
Let the cups holded by the small pitcher be x and the cups holded by the larger pitch be y
Given Two small pitchers and one large pitcher can hold 8 cups of water
ie 2x+y=8
Also given that One large pitcher minus one small pitcher constitutes 2 cups of water
ie y-x=2
subtract those two equation's we get
3x=6
x=2.
substitute this value of x is the second equation we get
y-2=2
y=4
Therefor the number of cups of water holded by small pitcher is 2 and the number of cups of water holded by large pitcher is 4.
