Question

What is the distance between the p&ints (8, 3) and (8, - 6) ?
O
3 units
O
8 units
O
9 units
o
17 units

Answer 1

Answer:

Using distance formula:

$d = \sqrt{(8 - 8 {)}^{2} + ( - 6 - 3) {}^{2} } = 9$

Answer: 9 units

Answer 2

Answer:

$\displaystyle 9\:units$

Step-by-step explanation:

Use the Distance Formula:

$\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[-8 + 8]^2 + [-3 - 6]^2} = \sqrt{0^2 + [-9]^2} = \sqrt{0 + 81} = \sqrt{81} = 9$

Since we are talking about distance, we ONLY want the NON-NEGATIVE root.

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