One hosta cost $8 and one pot of ivy cost $3.
Step-by-step explanation:
Let,
Hostas = x
Pot of ivy = y
According to given statement;
7x + 3y = 65 Eqn 1
3x + 3y = 33 Eqn 2
[tex]Subtracting\ Eqn\ 2\ from\ Eqn\ 1\\(7x+3y)-(3x+3y)=65-33\\7x+3y-3x-3y=32\\4x=32\\Dividing\ both\ sides\ by 4\\\frac{4x}{4}=\frac{32}{4}\\x=8\\[/tex]
Putting value of x in Eqn 1;
[tex]7(8)+3y=65\\56+3y=65\\3y=65-56\\3y=9\\Dividing\ both\ sides\ by\ 3\\\frac{3y}{3}=\frac{9}{3}\\y=3[/tex]
One hosta cost $8 and one pot of ivy cost $3.
Keywords: Linear Euqations, Addition.
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