Answer:
[tex]F = 75.1 N[/tex]
Explanation:
Here we know that torque due to applied force on the crank must be balanced by the torque due to weight of bucket on the cylinder
so here we know that
torque due to weight is given as
[tex]\tau_1 = r F[/tex]
[tex]\tau_1 = 0.073 \times 43 \times 9.81[/tex]
[tex]\tau_1 = 30.8 Nm[/tex]
now the torque by applied force on the crank is given as
[tex]\tau_2 = 0.41 F[/tex]
so we have
[tex]0.41 F = 30.8[/tex]
[tex]F = 75.1 N[/tex]