Question

In a particular crash test, an automobile of mass 1573 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 16 m/s and 2.6 m/s, respectively. If the collision lasts for 0.09 s, find the magnitude of the impulse due to the collision.

Answer 1

Answer:

$Impulse = 29257.8 kg m/s$

Explanation:

As we know that impulse due to collision is defined as the change in the linear momentum

So it is given as

$Impulse = \Delta P$

so we will have

$Impulse = m\vec v_f - m \vec v_i$

here we know that

$v_f = 2.6 m/s$

$v_i = -16 m/s$

mass of the car is given as

$m = 1573 kg$

now we have

$Impulse = 1573(2.6 + 16)$

$Impulse = 29257.8 kg m/s$