Question

A sled and rider with a combined mass of 70 kg are at the top of a hill of height 9 m above the level ground below. The sled is given a push providing an initial kinetic energy of 1200 J at the top of the hill. What will be the kinetic energy of the sled and rider at the bottom of the hill, if friction can be ignored?

Answer 1

Answer:

$K_p=6174J$

Explanation:

Given:

$m=70kg$,$m=9m$,$K_E=70kg$

$K_E=\frac{1}{2}*m*v^2$

$1200J=\frac{1}{2}*70kg*v^2$

$v=5.8m/s$

To determine the kinetic energy at the bottom is:

$K_p=m*g*h$

$K_p=70kg*9.8m/s^2*9m$

$K_p=6174J$