Answer:
[tex]9\dfrac{1}{4}[/tex]
[tex]4\dfrac{5}{8}[/tex]
Step-by-step explanation:
The master chief has three and a half cookies i.e. [tex]3\dfrac{1}{2} = \dfrac{7}{2}[/tex] numbers of cookies.
Again the arbiter has five and three quarters of a cookie i.e. [tex]5\dfrac{3}{4} = \dfrac{23}{4}[/tex] number of cookies.
Therefore, in total there are [tex](\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4}[/tex] numbers of cookies.
If we divide the total number of cookies in to equal parts and distribute to then then each of them will get [tex]\dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8}[/tex] numbers of cookies. (Answer)
