Question

A large beaker of water is placed on a scale, and the scale reads 40 N. A block of wood with a weight of 10 N is then placed in the beaker. It floats with exactly half of its volume submerged. Assuming that none of the water spilled out of the beaker when the block was added, what does the scale read now? (3 points)[ ] 40 N [ ] 45 N [ ] 50 N

Answer 1

Answer:

F = 50 N

Explanation:

As we know that block is floating in the water with half of the volume submerged into it

So we will have

$F_b = mg$

at equilibrium position the buoyancy force on the block will be equal to the weight of the block

Now the weight machine will measure the net normal force for which we have

$F_n = W + F_b$

so here we have

$F_n = 40 + 10$

$F_n = 50 N$