Question

an object initially traveling at 20 meters per second South accelerates uniformly at 6.0 meters per second squared and is displaced 25 M calculate the final velocity of the object​

Answer 1

Explanation:

Given:

Δx = 25 m

v₀ = 20 m/s

a = 6.0 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (20 m/s)² + 2 (6.0 m/s²) (25 m)

v ≈ 26.5 m/s

Answer 2

The final velocity of the object​ is 26.46 m/s.

Given the following data:

• Initial velocity = 20 m/s

• Acceleration = 6 $m/s^2$

• Displacement = 25 meters.

To find the final velocity of the object, we would use the third equation of motion;

$V^2 = U^2 + 2aS\\\\V^2 = 20^2 + 2(6)(25)\\\\V^2 = 400 + 300\\\\V^2 = 700\\\\V = \sqrt{700}$

Final velocity, V = 26.46 m/s

Therefore, the final velocity of the object​ is 26.46 m/s.

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