According to the question,
The kinetic energy will be:
= [tex]\frac{1}{2}mv^2[/tex]
By substituting the values, we get
= [tex]\frac{1}{2}\times 6\times (3)^2[/tex]
= [tex]\frac{1}{2}\times 6\times 9[/tex]
= [tex]27 \ J[/tex]
Thus the answer above is right.
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