For this case we have the following equation:
[tex]\frac {4} {5} x + \frac {1} {2} y = 40[/tex]
We must find the intersections with the x and y axes respectively.
Intersection with the x axis: Making[tex]y = 0[/tex] we have:
[tex]\frac {4} {5} x + \frac {1} {2} (0) = 40\\\frac {4} {5} x = 40[/tex]
We multiply by 5 on both sides of the equation:
[tex]4x = 5 * 40\\4x = 200[/tex]
Dividing by 4 to both sides of the equation:
[tex]x = \frac {200} {4}\\x = 50[/tex]
Thus, the intersection with the x-axis is given by: [tex](x, y) :( 50,0)[/tex]
Intersection with the y axis: Making[tex]x = 0[/tex]we have:
[tex]\frac {4} {5} (0) + \frac {1} {2} y = 40\\\frac {1} {2} y = 40[/tex]
We multiply by 2 on both sides of the equation:
[tex]y = 2 * 40\\y = 80[/tex]
Thus, the intersection with the y-axis is given by: [tex](x, y) :( 0,80)[/tex]
Answer:
Intersection with the x axis: (50,0)
Intersection with the y axis: (0,80)