Question

For which values of the variables the following equality is true?
$\frac{3a^{2}+ac+2c-6a }{3a-c} =a-2$

Answer 1

Answer:

For The value of a = 0 and c = 0 , The given expression equality is true  

Step-by-step explanation:

Given expression as :

$\frac{3a^{2}+ac+2c-6a}{3a - c}$ = a - 2

Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )

Or, 3 a² + ac + 2 c - 6 a =  3 a² - ac - 6 a + 2 c

Or, (  3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0

Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0

or,  0 + 2 ac + 0

Or, 2 ac = 0

∴  a =0  and c = 0

Hence For The value of a = 0 and c = 0 , The given expression equality is true  .  Answer