The kinetic energy increases by 4 times
Explanation:
The kinetic energy of a moving object is given by:
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is its speed
Looking at the equation, we see that the kinetic energy is proportional to the square of the speed of the object.
In this problem, the initial speed is
v = 30 mph
Let's assume that the corresponding kinetic energy is K.
Later, the speed is doubled to
v' = 2v = 60 mph
So, the new kinetic energy is
[tex]K' = \frac{1}{2}mv'^2 = \frac{1}{2}m(2v)^2 = 4(\frac{1}{2}mv^2)=4K[/tex]
So, the kinetic energy will quadruple.
Learn more about kinetic energy:
brainly.com/question/6536722
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