Question

What is the length of the hypotenuse of the triangle?

Answer 1

It is given by Pythagoras Theorem that

$h^2=a^2+b^2$

where h is hypotenuse.

We solve for h to get

$h=\sqrt{a^2+b^2}=\sqrt{3^2+7^2}=\boxed{\sqrt{58}}$

Hope this helps.

Answer 2

Answer:

$\sqrt{58}$

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to find hypotenuse

The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

AB² = BC² + AC²

AB² = 3² + 7² = 9 + 49 = 58 ( take the square root of both sides )

AB = $\sqrt{58}$