Question

Find the 57th term of the following arithmetic sequence.
6, 15, 24, 33, ...

Answer 1

Answer:

510

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 6 and d = 15 - 6 = 9, thus

$a_{57}$ = 6 + (56 × 9) = 6 + 504 = 510