contestada

A 50kg football player heading to the right at 2.5 m/s
collides with and tackles a 40kg player heading left at 3.5
m/s toward him. What is the speed and direction of the
tangled players?

Respuesta :

Answer:

The speed of the tangled players is [tex]0.17\ ms^{-1}[/tex] in left direction

Explanation:

Mass of Player 1 =[tex]m_1[/tex] = [tex]50\ kg[/tex]

Mass of Player 2 =[tex]m_2[/tex] = [tex]40\ kg[/tex]

Velocity of Player 1 moving right =[tex]v_1=2.5\ ms^{-1}[/tex]

Velocity of Player 2 moving left =[tex]v_2=-3.5\ ms^{-1}[/tex]

By law of conservation of momentum:

[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]

Here [tex]v[/tex] represents the velocity of tangled players.

Plugging in values in the equation.

[tex](50\times2.5)+(40\times(-3.5))=(50+40)v\\125-140=90v\\-15=90v\\[/tex]

Dividing both sides by 90.

[tex]\frac{-15}{90}=\frac{90v}{90}\\-0.167=v[/tex]

∴ [tex]v=0.167\approx 0.17\ ms^{-1}[/tex]

The negative velocity indicates that the tangled players move to the left after collision.

The speed of the tangled players is [tex]0.17\ ms^{-1}[/tex] in left direction

ACCESS MORE