During the Christmas season, a store offers a sale. You buy one item for the regular price then you get 60% discount on a second item of equal or less value. If you buy two items with regular prices of $30 and $20 by what percent will the total cost of two items reduce during the sale?

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Answer:

24%

Step-by-step explanation:

we know that

You buy one item for the regular price then you get 60% discount on a second item of equal or less value

so

You buy one item by $30 (regular price) and the other item of $20 get 60% discount

100%-60%=40%=40/100=0.40

The total cost of the two items with discount is

$30+0.40($20)=$38

The total cost of the two items without  discount is

$30+$20=$50

The total cost reduce is

$50-$38=$12

Convert to percentage

[tex]\frac{\$50}{100\%}=\frac{\$12}{x}\\\\x=100\%(12)/50\\\\x= 24\%[/tex]

Answer:

24 percent

Step-by-step explanation

(this is calculus so...) the disorient angle of the 60 percent is equal to the angle displacement of the 30 and 20. 30+20=50.

then 60*5=300.

300/12.5=24

12.5 because the ray vector of the disorient is equal to pq/c^3*50

hoping u know the constant of disorient . . .u get 12.5

divide 300 by 12.5 to get 24.

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