Question

if the sum of two number is 56 and smaller one is 8 less then the bigger one find the number
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Answer 1

Answer:

32 AND 24

Step-by-step explanation:

LET THE NUMBERS BE X AND Y

X= THE BIGGER NUMBER

Y=THE SMALLER NUMBER

X+(X-8)=56

2X-8=56

2X=56+8

2X=64

X=32

X+(X-8)

32+(32-8)

32+24

56

Answer 2

Answer:

The bigger numbers is 32  

The smaller numbers is 24    

Step-by-step explanation:

Given as :

Let the first number = x

The second number = x - 8

The sum of two number = 56

Or, x + ( x - 8 ) = 56

Or, 2 x = 56 + 8

Or, 2 x = 64

∴       x = $\frac{64}{2}$ = 32

So, The first number = x = 32

    The second number = 32 - 8 = 24

Hence The bigger numbers is 32  

           The smaller numbers is 24    Answer