Answer:
Volume = 29400 cm³
Mass = 21.6 g
Explanation:
Given data:
Number of moles of water vapors = 1.2 mol
Mass of water vapor = ?
Volume of water vapors = ?
Solution:
Room temperature = 25 °C (25+273 = 298 K)
Room pressure = 1 atm
PV = nRT
V = nRT/P
V = 1.2 mol × 0.0821 atm. K⁻¹. mol⁻¹ . L × 298 K/ 1 atm
V = 29.4 L
In cm³:
29.4 × 1000 = 29400 mL
mL = cm³
Mass of water vapors:
Mass = number of moles × molar mass
Mass = 1.2 mol × 18 g/mol
Mass = 21.6 g
