Answer:
$140(each square),$140(semi sphere),$140(each quarter ring)
Total=$980
Step-by-step explanation:
Given
- 4 squares of side 20 in
- 1 semi circle of radius 10 in(half of side of square as seen in figure)
- 2 quarter rings of thickness 10 and inner radius 10 and outer radius 20
Each square are[tex]=side^{2} =20^{2} =400\\[/tex]
Therefore each square costs=$140
⇒Total cost for squares=[tex]=4\times 140=560[/tex]
Area of semi circle[tex]=(pie)\times radius^{2}=(pie)\times 10^{2} =314.2..[/tex]
⇒Cost for semi-circle= $140
Area of each quarter ring[tex]=\frac{((pie)\times outer^{2})-((pie)\times inner^{2})}{2} =\frac{(pie)\times (20^{2}-10^{2})}{2} =\frac{(pie)\times 300}{2} =471.23..[/tex]
⇒Cost of each quarter-circle= $140
⇒Cost of both quarter-circle= $140+$140=$280
Therefore total cost for window=$280+$140+$560=$980
