Write the quadratic equation that has roots √3 +1/2 and √3 −1/2 , if its coefficient with x^2 is equal to


Answer: [tex]x^{2}[/tex] + [tex]\sqrt{3}[/tex]x + 0.5 = 0
Step-by-step explanation:
The formula for finding the quadratic equation with given roots
⇒[tex]x^{2}[/tex] - sum of roots(x) + product of roots = 0
Sum of roots = [tex]\frac{\sqrt{3}-1 }{2}[/tex] + [tex]\frac{\sqrt{3}+1 }{2}[/tex]
= 2[tex]\sqrt{3}[/tex]
Product of roots⇒
[tex]\frac{\sqrt{3}-1 }{2}[/tex] X [tex]\frac{\sqrt{3}+1 }{2}[/tex]
= 1/2 = 0.5
substituting into the formula , we have
[tex]x^{2}[/tex] +[tex]\sqrt{3}[/tex]x + 0.5 = 0