Question

If y = f(x) = 2(4)x + c, find the value of "c" that results in a graph with x-intercept at (2, 0).
A) −32
B) −8
C) 32
D) 8

Answer 1

Answer:

Option A) −32

Step-by-step explanation:

we have

$f(x)=2(4)^{x}+C$

we know that

For x=2, f(x)=0 ----> given problem

so

substitute the value of x and the value of f(x) in the function above and solve for C

$0=2(4)^{2}+C$

$0=2(16)+C$

$0=32+C$

$C=-32$