Answer:
The speed relative to the spaceship when she try to reach it is 0.78m/s
Explanation:
To solve this problem it is necessary to apply the concepts related to energy conservation, in which the mass and velocity of the object must be equal to the mass released and the velocity acquired by the astronaut.
The equation given to solve the problem is given by:
[tex]m_1v_1=m_2v_2[/tex]
Where,
[tex]m_1 =[/tex] Mass without tank
[tex]v_1 =[/tex]Velocity of the astronaut
[tex]m_2 =[/tex] Mass removed
[tex]v_2 =[/tex]velocity of the removed mass
Our dates are given by,
[tex]m_1 = 60-3 = 57kg[/tex]
[tex]m_2 = 3kg[/tex]
[tex]v_2 = 15m/s[/tex]
Replacing the values
[tex](57)v_2 = (3)(15)[/tex]
[tex]v_2 = \frac{3*15}{57}[/tex]
[tex]v_2 = 0.78m/s[/tex]
Therefore the speed relative to the spaceship when she try to reach it is 0.78m/s