Question

What is the molarity of ZnCl2 that forms when 25.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 285 mL .
Zn(s)+CuCl2(aq)→ZnCl2(aq)+Cu(s)

Answer 1

The ZnCl₂ solution have a molarity of 1.33 M.

Explanation:

We have the following chemical reaction:

Zn (s) + CuCl₂ (aq) → ZnCl₂ (aq) + Cu (s)

number of moles = mass / molar weight

number of moles of Zn = 25 / 65.4 = 0.38 moles

From the chemical equation we see that 1 moles of Zn produces 1 mole of ZnCl₂, so 0.38 moles of Zn will produce 0.38 moles of ZnCl₂.

molarity = number of moles / volume (L)

molarity of the ZnCl₂ solution = 0.38 / 0.285 = 1.33 M

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